Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 35 - Interference - Problems - Page 1076: 38a

Answer

The longest wavelength is $567nm$

Work Step by Step

We know that $2L=\frac{m\lambda}{n}$ This can be rearranged as: $\lambda=\frac{2nL}{m}$ We plug in the known values to obtain: $\lambda=\frac{2(1.70)(5\times 10^{-7})}{m}=\frac{1700nm}{m}$ for $m=1$; $\lambda=\frac{1700nm}{1}=1700nm$ for $m=2$; $\lambda=\frac{1700nm}{2}=850nm$ for $m=3$; $\lambda=\frac{1700nm}{3}=567nm$ Hence the longest wavelength is $567nm$.
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