Answer
The amplitude of the resultant electric field is $~~2.32~\mu V/m$
Work Step by Step
$\sum~E_h = (2.00~\mu V/m)+(2.00~\mu V/m)~cos~(39.6~rad) = 1.35~\mu V/m$
$\sum~E_v = (0)+(2.00~\mu V/m)~sin~39.6~rad = 1.89~\mu V/m$
We can find the amplitude:
$E = \sqrt{(1.35~\mu V/m)^2+(1.89~\mu V/m)^2} = 2.32~\mu V/m$
The amplitude of the resultant electric field is $~~2.32~\mu V/m$
