Answer
Point P lies between the central maximum and the first minimum.
Work Step by Step
We can find the angle $\theta$:
$\theta =tan^{-1}~(\frac{0.205~m}{4.00~m}) = 0.0512~rad$
The angles of the maxima have the form:
$\theta_m = \frac{m~\lambda}{d} = m~\frac{580~nm}{4.50~\mu m} = m~(0.129~rad)$
The angles of the minima have the form:
$\theta_m = \frac{(m+0.5)~\lambda}{d} = (m+0.5)~\frac{580~nm}{4.50~\mu m} = (m+0.5)~(0.129~rad)$
Note that the first minimum occurs at the angle $~~0.064~rad$
Since the angle at point P is less than the angle at the first minimum, point P lies between the central maximum and the first minimum.
