Answer
The phasors would rotate around the origin at the angular speed of $~~\omega = 1.26\times 10^{15}~rad/s$
Work Step by Step
$\omega = 1.26\times 10^{15}~rad/s$
Therefore, the phasors would rotate around the origin at the angular speed of $~~\omega = 1.26\times 10^{15}~rad/s$
