Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 34: 32

Answer

Acceleration = -20.6g

Work Step by Step

Given: $V_{o}$ = 1020km/hr = 283.33 m/s time = 1.4s What we know: $V_{f}$ = 0 1g = 9.8m/$s^{2}$ Use the equation: Acceleration = $\frac{V_{f}-V_{o}}{t}$ Acceleration = $\frac{0m/s^{2}-283.33m/s^{2}}{1.4 seconds}$ Acceleration = -202.3m/$s^{2}$ To find the answer in terms of g: Acceleration = $\frac{(-283.33m/s^{2})(1g)}{9.8m/s^{2}}$ Acceleration = -20.6g
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