Answer
The graph for $x$ versus $t$ for the deceleration is parabolic and increasing. Furthermore, the graph for $v$ versus $t$ for the deceleration is decreasing.
Work Step by Step
deceleration $a=4.92$ $m/s^{2}$
initial velocity $V_{i}=24.6$ $m/s$
final velocity $V_{f}=0$
Since $V_{f}=V_{i}-at$, then, substituting the given, we get the travel time $t$ ($s$)
$$t=\frac{V_{i}}{a}=\frac{24.6}{4.92}=5$$
Also, the distance traveled $x$ ($m$)
$$x=V_{i}t-\frac{1}{2}at^{2}=(24.6)(5)-\frac{1}{2}(4.92)(5)^{2}=61.5$$
Using the above results in the time range $0\leq t \leq5$ $s$, the graph for $x$ versus $t$ for the deceleration is parabolic and increasing. Furthermore, the graph for $v$ versus $t$ for the deceleration is decreasing.
