Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 34: 31a

Answer

3.1 x 10$^6$ seconds

Work Step by Step

We have an initial velocity of 0 m/s with a constant acceleration of 9.8 m/s$^2$. We also know that our end velocity is one tenth the speed of light (3 x 10$^8$m/s). Using $v=v_{0}+at$, we solve for $t$. $t=\frac{(1/10)(3\times10^8m/s)}{(9.8m/s^2)}=3.1\times10^6s$
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