Answer
Function for x versus t: $x = 2.50\times10^{6}t$
(see attached image for graph)
Function for v versus t: $v = -1.25\times10^{14}t$
(see attached image for graph)
Work Step by Step
The question asks you to graph the movement of the muon two different ways:
1) x versus t
2) v versus t
To graph the movement of the particle as a function of distance over time (x versus t), it is important to recognize that velocity is given by distance divided by time. Knowing this (and that a ~constant~ acceleration is given in the problem) you can easily find the function that relates distance to time ( x = V avg * t )and simply graph it. (see attached image)
To graph the movement of the particle as a function of velocity over time (v versus t), you must recognize that acceleration is given by velocity divided by time. Knowing this, you can easily find the function that relates velocity to time ( v = a*t) and simply graph it. (see attached image)
