Answer
4.6 x 10$^{13}$ m
Work Step by Step
Since both initial distance and initial velocity are 0, we can solve for the distance traveled by using $x=\frac{1}{2}at^2$. We simply plug in the values for $a$ and $t$.
$x=(0.5)(9.8m/s^2)(3.1\times10^6s)^2=4.6\times10^{13}m$
