Answer
The maximum transverse speed is $~~3.77~m/s$
Work Step by Step
Since the bar moves through a distance of $1.00~cm$, then the amplitude is $y_m = 0.500~cm$
The frequency is $120~Hz$
We can find the maximum transverse speed:
$u_{max} = \omega~y_m$
$u_{max} = 2\pi~f~y_m$
$u_{max} = (2\pi)~(120~Hz)~(0.00500~m)$
$u_{max} = 3.77~m/s$
The maximum transverse speed is $~~3.77~m/s$
