Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 476: 65d

Answer

$\lambda=31cm$

Work Step by Step

We can find the wavelength as $\lambda=\frac{2\pi}{k}$ We plug in the known values to obtain: $\lambda=\frac{2\pi}{k}=\frac{2(3.1416)}{20}=0.31m=31cm$
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