Answer
$v_m=1.2\frac{m}{s}$
Work Step by Step
We can find the maximum transverse speed as
$v_m=y_m\omega$
We plug in the known values to obtain:
$v_m=(2.0)(600)=1200\frac{mm}{s}=\frac{1200}{1000}\frac{m}{s}=1.2\frac{m}{s}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 16 - Waves-I - Problems - Page 476: 65e
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