Answer
$f=95Hz$
Work Step by Step
The given equation is $y=(2.0mm)sin[(20m^{-1})x]-(600s^{-1})t]$
By comparing the given equation with $y_(x,t)=y_m sin(kx-\omega t)$ we obtain:
$\omega=600\frac{rad}{s}$
As we know that $\omega=2\pi
f$
Hence $f=\frac{\omega}{2\pi}$
We plug in the known values to obtain:
$f=\frac{600}{2(3.1416)}=95Hz$
