Answer
$20\pi\;m^{-1}$
Work Step by Step
The wavelength of the wave is given $\lambda=10\;cm=0.1\;m$
Now, the wavenumber $(k)$ is given by
$k=\frac{2\pi}{\lambda}$
or, $k=\frac{2\pi}{0.1}\;m^{-1}$
or, $k=20\pi\;m^{-1}$
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