Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 476: 62b

Answer

$20\pi\;m^{-1}$

Work Step by Step

The wavelength of the wave is given $\lambda=10\;cm=0.1\;m$ Now, the wavenumber $(k)$ is given by $k=\frac{2\pi}{\lambda}$ or, $k=\frac{2\pi}{0.1}\;m^{-1}$ or, $k=20\pi\;m^{-1}$
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