Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 473: 23g

Answer

$\omega = 190~s^{-1}$

Work Step by Step

We found that $T = 0.033~s$ We can find $\omega$: $\omega = \frac{2\pi}{T}$ $\omega = \frac{2\pi}{0.033~s}$ $\omega = 190~s^{-1}$
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