Answer
$v=129\frac{m}{s}$
Work Step by Step
As
$v=\sqrt{\frac{T}{\mu}}$
but linear mass density $'\mu'=\frac{m}{L}$
thus $v=\sqrt{\frac{T}{\frac{m}{L}}}$
$v=\sqrt{\frac{TL}{m}}$
putting the values, we get
$v=\sqrt{\frac{(500N)(2m)}{0.060kg}}$
$v=129\frac{m}{s}$
