Answer
The maximum transverse speed is $~~9.4~m/s$
Work Step by Step
We found that $y_m = 0.050~m$ and $T = 0.0333~s$
We can find the maximum transverse speed:
$v_{max} = y_m \omega$
$v_{max} = \frac{2\pi y_m}{T}$
$v_{max} = \frac{(2\pi)(0.050~m)}{0.0333~s}$
$v_{max} = 9.4~m/s$
The maximum transverse speed is $~~9.4~m/s$
