Answer
$v = 15~m/s$
Work Step by Step
$y = (y_m) ~sin(kx-\omega t)$
$y = (0.021~m) ~sin[(2.0 ~m^{-1})x-(30 ~s^{-1}) t]$
We can find the wave speed:
$v = \frac{\omega}{k}$
$v = \frac{30~s^{-1}}{2.0~m^{-1}}$
$v = 15~m/s$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 16 - Waves-I - Problems - Page 473: 17a
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