Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 473: 22a

Answer

$f=\frac{2}{\pi}$ Hz

Work Step by Step

Comparing the given equation $y=(5.0cm)sin[1.0-(4.0 s^{-1})t]$ to $(x,t)=y_m sin(kx-\omega t)$ we obtain: $\omega t=4 s^{-1}t$ $\omega=4 s^{-1}$ We know that $\omega=2\pi f$. This can be written as $f=\frac{\omega}{2\pi}$. We plug in the known values to obtain: $f=\frac{4}{2\pi}=\frac{2}{\pi}Hz$
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