Answer
The two pulses meet at $~~x = 2.63~m$
Work Step by Step
We can find the wave speed on the wire:
$v = \sqrt{\frac{\tau}{\mu}}$
$v = \sqrt{\frac{250~N}{0.100~kg/10.0~m}}$
$v = 158.1~m/s$
We can find the position of the first pulse at $t = 30~ms$:
$x = x_0-vt$
$x = (10.0~m)-(158.1~m/s)(0.0300~s)$
$x = 5.257~m$
After this, the two pulses travel along the wire at the same speed in opposite directions, so they meet at the halfway point of $x = 5.257~m$, which is $x = 2.63~m$
The two pulses meet at $~~x = 2.63~m$
