Answer
$1Mn(OH)_3(s) \lt -- \gt 1Mn^{3+}(aq) + 3OH^-(aq)$
$K_{sp} (Mn(OH)_3) = [Mn^{3+}][OH^-]^3$
Work Step by Step
- Manganese (III) $(Mn^{3+})$ hydroxide $(OH^-)$: $Mn(OH)_3$
1. Write the dissociation equation for this salt:
- Identify the ions of the salt: $(Mn^{3+})$ and $(OH)$, these are the products, and the reactant is the solid salt.
$Mn(OH)_3(s) \lt -- \gt Mn^{3+}(aq) + OH^-(aq)$
- Balance the equation:
$1Mn(OH)_3(s) \lt -- \gt 1Mn^{3+}(aq) + 3OH^-(aq)$
2. Now, write the $K_{sp}$ expression.
- Multiply the concentrations of the ions;
- The equilibrium coefficients represent the exponent of these concentrations:
$K_{sp} (Mn(OH)_3) = [Mn^{3+}]^1 \times [OH^-]^3$
