Answer
The necessary volume for this titration is $28\ ml \ NaOH$ .
Work Step by Step
1. Find the volume necessary for an equal number of moles:
$ (HBr) C_1 * V_1 = (NaOH) C_2 * V_2$
$ 0.315* 20= 0.225 * V_2$
$ 6.3 = 0.225 * V_2$
$V_2 = 28ml$