Answer
The necessary volume for this titration is $600ml$ of $HCl$.
Work Step by Step
1. Find the volume necessary for an equal number of moles:
$C_1 * V_1 = C_2 * V_2$
$ 6.0* 15= 0.15 * V_2$
$ 90 = 0.15 * V_2$
$V_2 = 600 ml$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 15 - Additional Aqueous Equilibria - Questions for Review and Thought - Topical Questions - Page 693b: 41b
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