Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 15 - Additional Aqueous Equilibria - Questions for Review and Thought - Topical Questions - Page 693b: 42b

Answer

The necessary volume for this titration is $33.3\ ml$ of $NaOH$

Work Step by Step

1. Find the volume necessary for an equal number of moles: $(HClO_4)C_1 * V_1 = (NaOH)C_2 * V_2$ $ 0.250* 30= 0.225 * V_2$ $ 7.5 = 0.225 * V_2$ $V_2 = 33.33ml$
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