Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 15 - Additional Aqueous Equilibria - Questions for Review and Thought - Topical Questions - Page 693b: 35d

Answer

Bromthymol blue is the most suitable, because it changes its color in neutral solutions, and the equivalence point of the titration between $KOH$ and $HNO_3$ is in neutral solution.

Work Step by Step

$HNO_3 $ is a strong acid and $KOH$ is a strong base; therefore, the pH at the equivalence point of their titration will be neutral $(pH = 7)$. Analyzing the 3 given indicators on page 667, the one where the color changes in neutral solution is the most appropriate, so Bromthymol blue is the correct answer.
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