Answer
$[H_3O^+] = 2.138 \times 10^{- 5}M$
$[OH^-] = 4.677 \times 10^{- 10}M$
This solution is acidic.
Work Step by Step
$[H_3O^+] = 10^{-pH}$
$[H_3O^+] = 10^{- 4.67}$
$[H_3O^+] = 2.138 \times 10^{- 5}M$
$[H_3O^+] * [OH^-] = Kw = 10^{-14}$
$ 2.138 \times 10^{- 5} * [OH^-] = 10^{-14}$
$[OH^-] = \frac{10^{-14}}{ 2.138 \times 10^{- 5}}$
$[OH^-] = 4.677 \times 10^{- 10}M$
$[H_3O^+] > [OH^-]$: Acidic solution.
Assuming $25^{\circ}C$: pH < 7: Acidic solution.
