Answer
$C_5H_5N(aq) + H_2O(l) \lt -- \gt C_5H_5NH^+(aq) + OH^-(aq)$
Work Step by Step
- Pyridine is a weak base, therefore, when $C_5H_5N$ reacts with water, it takes a proton from $H_2O$, producing $OH^-$ and $C_5H_5NH^+$.
- Since it produces $OH^-$, the solution will be considered $basic$.
