Answer
1.827g of $HCl$.
Work Step by Step
1. Use the pH to find the hydronium concentration.
$[H_3O^+] = 10^{-pH}$
$[H_3O^+] = 10^{- 1.3}$
$[H_3O^+] = 5.012 \times 10^{- 2}M$
- Since $HCl$ is a strong acid: $[HCl] = [H_3O^+]$
2. Calculate the number of moles: (HCl)
- 1000ml = 1L
$n(moles) = concentration(M) * volume(L)$
$n(moles) = 0.05012 * 1$
$n(moles) = 0.05012$
3. Find the mass value in grams: (HCl)
Molar mass (HCl) : 1.01* 1 + 35.45* 1 = 36.46g/mol
$mass(g) = mm(g/mol) * n(moles)$
$mass(g) = 36.46 * 0.05012$
$mass(g) = 1.827$
