Answer
$HCOOH(aq) + H_2O(l) \lt -- \gt HCOO^-(aq) + H_3O^+(aq)$
Work Step by Step
- Formic acid is an acid, therefore, when $HCOOH$ reacts with water, it will donate one proton to $H_2O$, and will produce $H_3O^+$ and $HCOO^-$
- Since it produces $H_3O^+$, the solution will be considered $acidic.$.
