Answer
The pH of the solution is 11.38, and its pOH is 2.62
Work Step by Step
$pOH = -log[OH^-]$
$pOH = -log( 2.4 \times 10^{- 3})$
$pOH = 2.62$
$pH + pOH = 14$
$pH + 2.62 = 14$
$pH = 11.38$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 14 - Acids and Bases - Questions for Review and Thought - Topical Questions - Page 652b: 30
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