Answer
The $pOH$ value of this solution is 12.505.
Work Step by Step
- Hydronium concentration $(H_3O^+)$ = 0.032M;
1. Calculate the pH value.
$pH = -log[H_3O^+]$
$pH = -log( 0.032)$
$pH = 1.495$
2. Use the pH value to calculate the pOH.
$pOH + pH = 14$
$pOH = 14 - pH = 14 - 1.495$
$pOH = 12.505$
