Answer
a. $ 0.200 \space M \space Cl^- $
b. $0.300 \space M \space Cl^- $
c. $0.300 \space M \space Cl^- $
Work Step by Step
1. Determine the amount of $Cl^-$ ions in each compound:
a. 1
b. 2
c. 3
2. Use them as conversion factors:
a. $$0.200 \space M \space NaCl \times \frac{1 \space mol \space Cl^-}{1 \space mol \space NaCl} = 0.200 \space M \space Cl^- $$
b. $$0.150 \space M \space SrCl_2 \times \frac{2 \space mol \space Cl^-}{1 \space mol \space SrCl_2} = 0.300 \space M \space Cl^- $$
c. $$0.100 \space M \space AlCl_3 \times \frac{3 \space mol \space Cl^-}{1 \space mol \space AlCl_3} = 0.300 \space M \space Cl^- $$
