Answer
$3.4\ g$
Work Step by Step
Number of moles:
$0.15\ M\times 250.\ mL=37.5\ mmol$
Mass:
$90.03\ mg/mmol\times 37.5\ mmol=3376.1\ Mg=3.4\ g$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179d: 48
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