Answer
See answer below.
Work Step by Step
Number of moles of $CO_2$:
$0.3718\ g\div 44.001\ g/mol=0.00845\ mol$
From stoichiometry:
$0.00845\ mol$ of C, $0.00845\ mol\times12.011\ g/mol=0.1015\ g$
Number of moles of $H_2O$:
$0.1522\ g\div 18.015\ g/mol=0.00845\ mol$
From stoichiometry:
$0.0169\ mol$ of H, $0.0169\ mol\times1.008\ g/mol=0.0170\ g$
Number of moles of O : $(0.1523-0.1015-0.0170)\ g\div 15.9994\ g/mol=0.00211\ mol$
H/O Ratio: $0.0169/0.00211=8.00$
C/O Ratio: $0.00845/0.00211=4.00$
Empirical formula: $C_4H_8O$
Molar mass of the empirical formula:
$72.11\ g/mol$
Ratio of the molar masses:
$72.1/72.11=1.00$
Molecular formula: $C_4H_8O$
