Answer
a) $C_5H_4$
b) $C_{10}H_8$
Work Step by Step
a) Number of moles of $CO_2$:
$0.364\ g\div 44.001\ g/mol=0.00827\ mol$
$0.00827\ mol$ of C
Number of moles of $H_2O$:
$0.0596\ g\div 18.015\ g/mol=0.00331\ mol$
$0.00662\ mol$ of H
H/C Ratio: $0.80=4/5$
Empirical formula:
$C_5H_4$
b) Molar mass of the empirical formula: $64.085\ g/mol$
$128.2/64.085=2.00$
Molecular formula:
$C_{10}H_8$