Answer
$Fe(CO)_5$
Work Step by Step
Number of moles of $CO_2$
$2.200\ g\div 44.001\ g/mol=0.050\ mol$
$0.050\ mol$ of CO
Number of moles of $Fe_2O_3$
$0.799\ g\div 159.69\ g/mol=0.005\ mol$
$0.010\ mol$ of Fe
Ratio: $5.00$
Empirical formula:
$Fe(CO)_5$