Answer
See answer below.
Work Step by Step
Number of moles of sodium carbonate:
$6.73\ g\div 105.988\ g/mol=0.0635\ mol$
Concentration:
$0.0635\ mol/0.250\ L=0.254\ M$
For the ions, from stoichiometry:
$Na^+$: $0.508\ M$
$CO_3^{2-}$: $0.254\ M$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179d: 39
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