Answer
Empirical formula:
$CH_3O$
Molecular formula:
$C_2H_6O_2$
Work Step by Step
Number of moles of $CO_2$:
$0.1356\ g\div 44.001\ g/mol=0.00308\ mol$
$0.00308\ mol$ of C, $0.0370\ g$
Number of moles of $H_2O$:
$0.0833\ g\div 18.015\ g/mol=0.00462\ mol$
$0.00925\ mol$ of H, $0.00932\ g$
Number of moles of O :
$(0.0956-0.0370-0.0093)\ g\div 15.9994\ g/mol=0.00308\ mol$
H/C Ratio: $3.00$
O/C Ratio: $1.00$
Empirical formula:
$CH_3O$
Molar mass of the empirical formula: $31.03\ g/mol$
$62.1/31.03=2.00$
Molecular formula:
$C_2H_6O_2$