Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Review Exercises - Page 285: 21

Answer

$\theta\approx 73.26^o$

Work Step by Step

RECALL: (1) $\theta = \text{arcsec}{(x)}\longrightarrow \sec{\theta}=x$ (2) $\sec{x} =\frac{1}{\cos{x}}$ This means that $\theta=\text{arcsec}(x) \\\longrightarrow \sec{\theta}=x \\\longrightarrow \cos{\theta}=\frac{1}{x}$ Thus, $\theta =\text{arcsec}(3.4723155) \\\longrightarrow\sec{\theta}=3.4723155 \\\longrightarrow \cos{\theta} = \frac{1}{3.4723155}$ Use the inverse cosine function of a scientific calculator in degree mode to obtain: $\theta = \arccos{\left(\frac{1}{3.4723155}\right)} \\\theta=73.26220613^o \\\theta\approx 73.26^o$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.