Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 Applications of Vectors - 7.5 Exercises - Page 342: 6

Answer

$u=4i-2j$

Work Step by Step

If $v =\left\langle a,b \right\rangle$, then $v = ai + bj$, where $ i = \left\langle 1,0 \right\rangle$ and $ j=\left\langle 0,1 \right\rangle$. Now given $u =\left\langle 4,-2 \right\rangle$ then, $u= 4i + (-2)j=4i-2j$ Therefore, the vector $u =\left\langle 4,-2 \right\rangle$ is written in $i, j$ form as $u=4i-2j$.
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