Answer
$\langle4, 4\sqrt 3\rangle$
Work Step by Step
$u=\langle a,b\rangle=\langle |u|\cos\theta,|u|\sin\theta\rangle$
Substitute $|u|=8$ and $\theta=60^\circ$:
$\langle a,b\rangle=\langle8\cos 60^\circ,8\sin60^\circ\rangle $
$\langle a,b\rangle =\langle 4,4\sqrt 3 \rangle$
