Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 626: 31

$8i -j$ and the position vector is: $(8, -1)$

If a vector $v$ initiates at point $A(x_1,y_1)$ and terminates at $B(x_2,y_2)$, then $v =\lt x_2-x_1, y_2-y_1 \gt =(x_2-x_1)i+(y_2-y_1) \ j$ Here, we have: $A=(-2,-1)$ and $B=(6, -2)$ Therefore, $v=(6-(-2))i+(-2-(-1)) \ j = 8i -j$ and the position vector is: $(8, -1)$