Answer
$3i-5j$ and the position vector is: $(-3,-5)$
Work Step by Step
If a vector $v$ initiates at point $A(x_1,y_1)$ and terminates at $B(x_2,y_2)$, then
$v =\lt x_2-x_1, y_2-y_1 \gt =(x_2-x_1)i+(y_2-y_1) \ j$
Here, we have: $A=(0,0)$ and $B=(-3,-5)$
Therefore, $v=(-3-0)i+(-5-0) \ j =-3i-5j$ and the position vector is: $(-3,-5)$