Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.3 The Complex Plane; De Moivre's Theorem - 8.3 Assess Your Understanding - Page 615: 25

Answer

$2 \sqrt 2 -2 \sqrt 2 \ i$

Work Step by Step

We know from the unit circle that: $\cos \dfrac{7 \pi}{4}=\dfrac{\sqrt 2}{2}$ and $\sin \dfrac{7 \pi}{4}=\dfrac{\sqrt 2}{2}$ Thus,, we simplify the given expression as follows: $4\left[\cos (\dfrac{7 \pi}{4})+i \ \sin (\dfrac{7 \pi}{4})\right] \\=4\left(\dfrac{\sqrt 2}{2}\right) - 4\left(i \dfrac{\sqrt 2}{2}\right) \\=2 \sqrt 2 -2 \sqrt 2 \ i$
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