Answer
$44^{\circ} 0^{'} 36^{"}$
Work Step by Step
RECALL:
$1^{\circ} = 60^{'} \text{ and } 1^{'} = 60^{"}$
\begin{equation}
\begin{split}
$44.01^{\circ} &= 44^{\circ}+0.01^{\circ} \\ & = 44^{\circ} + 0.01 \times (1)^{\circ} \\ & = 44^{\circ}+0.01 \times (60)^{'} \\ & = 44^{\circ}+0.6^{'} \\ & = 44^{\circ}+0^{'}+0.6^{'} \\ & = 44^{\circ}+0^{'}+0.6 \times (1)^{'} \\ & = 44^{\circ}+0^{'}+0.6 \times (60)^{"} \\ & = 44^{\circ}+0^{'}+ 36^{"}
\end{split}
\end{equation}
Thus, $44.01^{\circ} = 44^{\circ} 0^{'} 36^{"}$
