Answer
$ 29^{\circ} 24^{'} 40^{"}$
Work Step by Step
RECALL:
$1^{\circ} = 60^{'} \text{ and } 1^{'} = 60^{"}$
\begin{equation}
\begin{split}
29.411^{\circ} &= 29^{\circ}+0.411^{\circ} \\ &= 29^{\circ} + 0.411 \times (1)^{\circ} \\ & = 29^{\circ} + 0.411 \times (60)^{'} \\ & = 29^{\circ} + 24.66^{'} = 29^{\circ}+24^{'}+0.66^{'} \\ & = 29^{\circ}+24^{'}+0.66 \times (1)^{'} \\ & = 29^{\circ} + 24^{'} + 0.66 \times (60)^{"} \\ & = 29^{\circ} + 24^{'} + 39.6^{"} \\ & \approx 29^{\circ} + 24^{'} + 40^{"}
\end{split}
\end{equation}
Thus, $29.411^{\circ} = 29^{\circ} 24^{'} 40^{"}$
