Answer
$61^{\circ} 14^{'} 24^{"}$
Work Step by Step
RECALL:
$1^{\circ} = 60^{'} \text{ and } 1^{'} = 60^{"}$
\begin{equation}
\begin{split}
61.24^{\circ} = 61^{\circ}+0.24^{\circ} \\ & = 61^{\circ}+0.24 \times (1^{\circ}) \\ & = 61^{\circ}+0.24 \times (60^{'}) \\ & = 61^{\circ}+14.4^{'} \\ & = 61^{\circ}+14^{'}+0.4^{'} \\ & = 61^{\circ}+14^{'}+0.4 \times (1)^{'} \\ & = 61^{\circ}+14^{'}+0.4 \times (60)^{"} \\ & = 61^{\circ}+14^{'} + 24^{"}
\end{split}
\end{equation}
Thus, $61.24^{\circ} = 61^{\circ} 14^{'} 24^{"}$
