Answer
$f(x)=|x|$ and $g(x)=2x+1$
Work Step by Step
We wish to find two functions $f$ and $g$ such that:
$H(x)=(f \circ g)(x) =|2x+1|$
Let us consider:
$f(x)=|x|$ and $g(x)=2x+1$
Then we have the composite function:
$H(x)=(f \circ g)(x) =f[g(x)]=f(2x+1)=|2x+1|$
