Answer
$ (\frac{47}{16}, \frac{49}{16})$
See graph.
Work Step by Step
Step 1. $|(4x-1)-11|\lt \frac{1}{4}\longrightarrow |4x-12|\lt \frac{1}{4} \longrightarrow |x-3|\lt \frac{1}{16}$ can be separated into $-\frac{1}{16}\lt x-3\lt \frac{1}{16} \longrightarrow \frac{47}{16}\lt x\lt \frac{49}{16}$, thus we have the solution $ (\frac{47}{16}, \frac{49}{16})$
Step 2. See graph.