Chapter 2 - Linear and Quadratic Functions - Section 2.8 Equations and Inequalities Involving the Absolute Value Function - 2.8 Assess Your Understanding - Page 182: 56

$(-\infty,\frac{1}{3})\cup(1,\infty)$ See graph.

Step 1. $|2-3x|\gt|-1|$ or $|3x-2|\gt1$ can be separated into $3x-2\gt1$ or $3x-2\lt-1$ which lead to $x\gt1$ or $x\lt\frac{1}{3}$, thus we have the solution $(-\infty,\frac{1}{3})\cup(1,\infty)$ Step 2. See graph.